tag:blogger.com,1999:blog-4496851626208894005.post5136674707321260672..comments2020-09-17T07:38:24.008+01:00Comments on ECG Class - Keeping ECGs Simple: The Cardiac Axis - For 4 yr oldsHeather Wetherellhttp://www.blogger.com/profile/11571085381364473101noreply@blogger.comBlogger12125tag:blogger.com,1999:blog-4496851626208894005.post-53505305902890693972016-03-02T19:18:48.299+00:002016-03-02T19:18:48.299+00:00Can anyone help me with this quest
A patient is c...Can anyone help me with this quest<br /><br />A patient is connected to a three-lead ECG monitor that monitors Lead I, II and III waveform.<br /><br />a. If the Lead II peak amplitude is 11mm and the Lead III peak amplitude is 13 mm, what is the cardiac vector angle?<br />b. What peak amplitude is expected for the lead I waveform?<br />c. Include a Sketch of Einthoven’s triangle and the projections of the cardiac vector onto each lead axis.<br />d. Sketch 2-3 beats of each of the three ECG waveforms.<br />Anonymoushttps://www.blogger.com/profile/14760793065589383232noreply@blogger.comtag:blogger.com,1999:blog-4496851626208894005.post-41105852414954289182016-02-29T20:15:14.418+00:002016-02-29T20:15:14.418+00:00This is super helpful! Thank you very much :)This is super helpful! Thank you very much :)Mollyhttps://www.blogger.com/profile/18035152032606131025noreply@blogger.comtag:blogger.com,1999:blog-4496851626208894005.post-19822807159891176072015-10-20T12:59:16.876+01:002015-10-20T12:59:16.876+01:00I'm a med student and I love your method. than...I'm a med student and I love your method. thanks!Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-4496851626208894005.post-71021512593471815542014-01-08T21:30:04.759+00:002014-01-08T21:30:04.759+00:00Hi :) thanks so much for the explanation! Was real...Hi :) thanks so much for the explanation! Was really helpful! <br /><br />Just wanted to tell you : our professor told us tthatonce you find the lead that is perpendicular to the isoelecric lead, in order to know which value of this lead is actually the value of the cardiac axis, you look at the net amplituse of the QRS complex pf that lead and if it s positive, then you take the positive value of the perpendicular lead as the value for the cardiac axis. So, in for instance the third example, the answer ould be +150 deg..<br /><br />Is this correct? Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-4496851626208894005.post-39296983874527892272013-09-24T10:26:41.141+01:002013-09-24T10:26:41.141+01:00Hi thanks for the information
Right angle = 90 deg...Hi thanks for the information<br />Right angle = 90 degree angle Σφέτσιος Τάσοςhttps://www.blogger.com/profile/07767059750351773012noreply@blogger.comtag:blogger.com,1999:blog-4496851626208894005.post-81059123858808106832013-02-04T10:40:53.305+00:002013-02-04T10:40:53.305+00:00Thanks for explaining ..
but i did not get the ri...Thanks for explaining .. <br />but i did not get the right angles ? <br /><br />Anonymoushttps://www.blogger.com/profile/18181751740027303886noreply@blogger.comtag:blogger.com,1999:blog-4496851626208894005.post-940780806664711592013-02-01T17:11:48.686+00:002013-02-01T17:11:48.686+00:00Thanks. Quite useful for a 40 years old as well......Thanks. Quite useful for a 40 years old as well...Anonymoushttps://www.blogger.com/profile/15035422424831795683noreply@blogger.comtag:blogger.com,1999:blog-4496851626208894005.post-25188437155128570782013-01-09T01:47:33.554+00:002013-01-09T01:47:33.554+00:00hello mam
many thanks for the blog
radically simpl...hello mam<br />many thanks for the blog<br />radically simple presentation to determine the axis<br />kindly keep up the good work<br />regardsAnonymoushttps://www.blogger.com/profile/08872555854959811157noreply@blogger.comtag:blogger.com,1999:blog-4496851626208894005.post-64648456360122846572013-01-03T17:08:04.062+00:002013-01-03T17:08:04.062+00:00Hi Whitney. Thanks for your kind comments. And wel...Hi Whitney. Thanks for your kind comments. And well done! I agree - this should have read -30 ! The same write up applies - within normal limits but 'leftward' . I will correct it straight away. But thanks so much for spotting. Hundreds of people have read this post, and you are the first confident enough to point that out! Don't forget to add that to your PDP/Appraisal! :)Heather Wetherellhttps://www.blogger.com/profile/11571085381364473101noreply@blogger.comtag:blogger.com,1999:blog-4496851626208894005.post-80192198179191487822013-01-02T23:07:16.838+00:002013-01-02T23:07:16.838+00:00Hi there :)
First of all thanks for this great ex...Hi there :)<br /><br />First of all thanks for this great explanation. I understood the stuff really well. Just wanted to ask, is there is mistake in the answer to the third ecg or have I missed out on something? Im refering to the +30 .. should it be -30 since that is the number associated with aVL?<br /><br />Thanks :)Anonymoushttps://www.blogger.com/profile/09494625792434128628noreply@blogger.comtag:blogger.com,1999:blog-4496851626208894005.post-58777623312821149212012-11-09T21:46:12.637+00:002012-11-09T21:46:12.637+00:00Hi Jamie. Thanks for your comment and for taking t...Hi Jamie. Thanks for your comment and for taking time to look at my blog.<br />I can't disagree with you - The vector method is the traditionally taught method, and certainly the most accurate. If you are comfortable with that method, and good with numbers, then stick with it! <br />The problem is, not everyone is comfortable with the vector method, and many people find it quite difficult to get their head round it. This is just an alternative suggestion - and was really just done for a bit of fun! However, I got some great feedback - many doctors felt they had suddenly had a 'penny dropping moment' in finally understanding cardiac axis. <br />If you are required to calculate a cardiac axis to an accurate degree, such as in an exam setting, then I can't compete with the vector method! Go for it. :-)Heather Wetherellhttps://www.blogger.com/profile/11571085381364473101noreply@blogger.comtag:blogger.com,1999:blog-4496851626208894005.post-87573929535121120052012-11-06T17:40:02.457+00:002012-11-06T17:40:02.457+00:00We were taught the vector method, where you add up...We were taught the vector method, where you add up all the QRS deflections in I and make that the X axis at 0 degrees (right = positive). You then add up all the QRS deflections in III and make that the Y axis at 90 degrees (down = positive). You then draw the resultant vector and see what angle it's pointing at. e.g. if I adds up to +3 and III adds up to +III you end up with a vector at 45 degrees.<br />What do you think of this method? It seems to me more intuitive than wondering about what is at right angles to what all the time, but then I am quite a numbers/graphy type person!Jamienoreply@blogger.com